How the leak is calculated
Air escaping through a small hole at normal working pressure reaches the speed of sound in the hole. The flow then depends only on the hole area and the pressure inside the system:
ṁ = Cd · A · p0 · √(γ ÷ (R T)) · (2 ÷ (γ + 1))(γ+1)/(2(γ−1))
Wasted power = free air flow (m³/min) · specific power (kW per m³/min)
The calculator uses a discharge coefficient Cd of 0.9, air at 20 °C, and converts the mass flow to free air at atmospheric pressure.
What leaks cost
| Hole diameter | Air loss at 6 bar | Wasted power | Cost per year* |
|---|---|---|---|
| 1 mm | 1.0 l/s | 0.4 kW | about 450 |
| 2 mm | 3.9 l/s | 1.5 kW | about 1,800 |
| 3 mm | 8.7 l/s | 3.4 kW | about 4,100 |
| 5 mm | 24 l/s | 9.5 kW | about 11,400 |
| 10 mm | 97 l/s | 38 kW | about 45,500 |
* 8,000 hours per year, 6.5 kW per m³/min, electricity at 0.15 per kWh. Real leaks are rarely round holes; treat the results as an order of magnitude.
Where leaks hide
- Quick couplings and hose connections
- Pressure regulators, filters and lubricators
- Condensate drains stuck open
- Threaded joints and pipe flanges
- Old cylinders and valves on machines
A leak survey with an ultrasonic detector typically pays for itself within weeks. Repeat it once or twice a year, because new leaks appear constantly.